Search a number
-
+
2560465141951 is a prime number
BaseRepresentation
bin100101010000100111100…
…111011000000010111111
3100001210000012220000202111
4211100213213120002333
5313422313034020301
65240132250034451
7352662466415203
oct45204747300277
910053005800674
102560465141951
118a7983904382
1235429a718a27
131575b260b142
148bcda246b03
154690c0e3551
hex254279d80bf

2560465141951 has 2 divisors, whose sum is σ = 2560465141952. Its totient is φ = 2560465141950.

The previous prime is 2560465141937. The next prime is 2560465141957. The reversal of 2560465141951 is 1591415640652.

2560465141951 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2560465141951 - 29 = 2560465141439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2560465141895 and 2560465141904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2560465141957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280232570975 + 1280232570976.

It is an arithmetic number, because the mean of its divisors is an integer number (1280232570976).

Almost surely, 22560465141951 is an apocalyptic number.

2560465141951 is a deficient number, since it is larger than the sum of its proper divisors (1).

2560465141951 is an equidigital number, since it uses as much as digits as its factorization.

2560465141951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296000, while the sum is 49.

The spelling of 2560465141951 in words is "two trillion, five hundred sixty billion, four hundred sixty-five million, one hundred forty-one thousand, nine hundred fifty-one".