Base | Representation |
---|---|
bin | 1110111001110110101… |
… | …0000101111111101111 |
3 | 220110220102201120222101 |
4 | 3232131222011333233 |
5 | 13143341310043413 |
6 | 313343223555531 |
7 | 24333053114644 |
oct | 3563552057757 |
9 | 813812646871 |
10 | 256048127983 |
11 | 9965354732a |
12 | 41759bbbba7 |
13 | 1b1b7108c4b |
14 | c56db8bdcb |
15 | 69d8cabedd |
hex | 3b9da85fef |
256048127983 has 2 divisors, whose sum is σ = 256048127984. Its totient is φ = 256048127982.
The previous prime is 256048127953. The next prime is 256048128001. The reversal of 256048127983 is 389721840652.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 256048127983 - 29 = 256048127471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (256048127903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128024063991 + 128024063992.
It is an arithmetic number, because the mean of its divisors is an integer number (128024063992).
It is a 1-persistent number, because it is pandigital, but 2⋅256048127983 = 512096255966 is not.
Almost surely, 2256048127983 is an apocalyptic number.
256048127983 is a deficient number, since it is larger than the sum of its proper divisors (1).
256048127983 is an equidigital number, since it uses as much as digits as its factorization.
256048127983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 256048127983 in words is "two hundred fifty-six billion, forty-eight million, one hundred twenty-seven thousand, nine hundred eighty-three".
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