Base | Representation |
---|---|
bin | 100101010000101010000… |
… | …100011011001100010001 |
3 | 100001210010002100122200102 |
4 | 211100222010123030101 |
5 | 313422404103431231 |
6 | 5240140320302145 |
7 | 352663506353651 |
oct | 45205204331421 |
9 | 10053102318612 |
10 | 2560506311441 |
11 | 8a79a5073651 |
12 | 3542b0471955 |
13 | 1575bacc40a0 |
14 | 8bd018c2361 |
15 | 46910a26acb |
hex | 2542a11b311 |
2560506311441 has 32 divisors (see below), whose sum is σ = 2894924938752. Its totient is φ = 2246987635200.
The previous prime is 2560506311401. The next prime is 2560506311453. The reversal of 2560506311441 is 1441136050652.
It is a cyclic number.
It is not a de Polignac number, because 2560506311441 - 214 = 2560506295057 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2560506311395 and 2560506311404.
It is not an unprimeable number, because it can be changed into a prime (2560506311401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 217299236 + ... + 217311018.
It is an arithmetic number, because the mean of its divisors is an integer number (90466404336).
Almost surely, 22560506311441 is an apocalyptic number.
It is an amenable number.
2560506311441 is a deficient number, since it is larger than the sum of its proper divisors (334418627311).
2560506311441 is a wasteful number, since it uses less digits than its factorization.
2560506311441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16193.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 2560506311441 in words is "two trillion, five hundred sixty billion, five hundred six million, three hundred eleven thousand, four hundred forty-one".
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