Base | Representation |
---|---|
bin | 111010001110010000010000… |
… | …011000110111100010110111 |
3 | 1020120122200200111121122201102 |
4 | 322032100100120313202313 |
5 | 232030342112114020233 |
6 | 2304335111100320315 |
7 | 104636113525003526 |
oct | 7216202030674267 |
9 | 1216580614548642 |
10 | 256066225141943 |
11 | 74655092507157 |
12 | 2487742484309b |
13 | acb5c313b5868 |
14 | 47339585684bd |
15 | 1e90d0bb961e8 |
hex | e8e4106378b7 |
256066225141943 has 2 divisors, whose sum is σ = 256066225141944. Its totient is φ = 256066225141942.
The previous prime is 256066225141933. The next prime is 256066225141963. The reversal of 256066225141943 is 349141522660652.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 256066225141943 - 218 = 256066224879799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (256066225141933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128033112570971 + 128033112570972.
It is an arithmetic number, because the mean of its divisors is an integer number (128033112570972).
Almost surely, 2256066225141943 is an apocalyptic number.
256066225141943 is a deficient number, since it is larger than the sum of its proper divisors (1).
256066225141943 is an equidigital number, since it uses as much as digits as its factorization.
256066225141943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18662400, while the sum is 56.
The spelling of 256066225141943 in words is "two hundred fifty-six trillion, sixty-six billion, two hundred twenty-five million, one hundred forty-one thousand, nine hundred forty-three".
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