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2561063471 is a prime number
BaseRepresentation
bin1001100010100110…
…1011101000101111
320121111002111121122
42120221223220233
520221113012341
61102044251155
7120315452231
oct23051535057
96544074548
102561063471
1110a472098a
125b5840abb
1331a78c495
141a41c8251
15eec8d94b
hex98a6ba2f

2561063471 has 2 divisors, whose sum is σ = 2561063472. Its totient is φ = 2561063470.

The previous prime is 2561063437. The next prime is 2561063489. The reversal of 2561063471 is 1743601652.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2561063471 - 210 = 2561062447 is a prime.

It is a super-3 number, since 3×25610634713 (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2561063671) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280531735 + 1280531736.

It is an arithmetic number, because the mean of its divisors is an integer number (1280531736).

Almost surely, 22561063471 is an apocalyptic number.

2561063471 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561063471 is an equidigital number, since it uses as much as digits as its factorization.

2561063471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30240, while the sum is 35.

The square root of 2561063471 is about 50606.9508170567. The cubic root of 2561063471 is about 1368.1701592241.

The spelling of 2561063471 in words is "two billion, five hundred sixty-one million, sixty-three thousand, four hundred seventy-one".