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25613351130823 is a prime number
BaseRepresentation
bin1011101001011100100101…
…01100100001011011000111
310100200121112110221101221221
411310232102230201123013
511324122120342141243
6130250335554021211
75252334501253531
oct564562254413307
9110617473841857
1025613351130823
118185619a7a305
122a58057577807
13113a437067cc1
1464799b0d6851
152e63de5d5bed
hex174b92b216c7

25613351130823 has 2 divisors, whose sum is σ = 25613351130824. Its totient is φ = 25613351130822.

The previous prime is 25613351130817. The next prime is 25613351130827. The reversal of 25613351130823 is 32803115331652.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25613351130823 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25613351130823.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25613351130827) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12806675565411 + 12806675565412.

It is an arithmetic number, because the mean of its divisors is an integer number (12806675565412).

Almost surely, 225613351130823 is an apocalyptic number.

25613351130823 is a deficient number, since it is larger than the sum of its proper divisors (1).

25613351130823 is an equidigital number, since it uses as much as digits as its factorization.

25613351130823 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 43.

The spelling of 25613351130823 in words is "twenty-five trillion, six hundred thirteen billion, three hundred fifty-one million, one hundred thirty thousand, eight hundred twenty-three".