Base | Representation |
---|---|
bin | 1011101001011100100101… |
… | …01100100001011011000111 |
3 | 10100200121112110221101221221 |
4 | 11310232102230201123013 |
5 | 11324122120342141243 |
6 | 130250335554021211 |
7 | 5252334501253531 |
oct | 564562254413307 |
9 | 110617473841857 |
10 | 25613351130823 |
11 | 8185619a7a305 |
12 | 2a58057577807 |
13 | 113a437067cc1 |
14 | 64799b0d6851 |
15 | 2e63de5d5bed |
hex | 174b92b216c7 |
25613351130823 has 2 divisors, whose sum is σ = 25613351130824. Its totient is φ = 25613351130822.
The previous prime is 25613351130817. The next prime is 25613351130827. The reversal of 25613351130823 is 32803115331652.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25613351130823 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 25613351130823.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25613351130827) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12806675565411 + 12806675565412.
It is an arithmetic number, because the mean of its divisors is an integer number (12806675565412).
Almost surely, 225613351130823 is an apocalyptic number.
25613351130823 is a deficient number, since it is larger than the sum of its proper divisors (1).
25613351130823 is an equidigital number, since it uses as much as digits as its factorization.
25613351130823 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 43.
The spelling of 25613351130823 in words is "twenty-five trillion, six hundred thirteen billion, three hundred fifty-one million, one hundred thirty thousand, eight hundred twenty-three".
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