Base | Representation |
---|---|
bin | 100101010001101100011… |
… | …111001100100101010011 |
3 | 100001212222202010200112122 |
4 | 211101230133030211103 |
5 | 313432144340010442 |
6 | 5240443044044455 |
7 | 353033230025501 |
oct | 45215437144523 |
9 | 10055882120478 |
10 | 2561620625747 |
11 | 8a8417075467 |
12 | 35456169372b |
13 | 157737b17271 |
14 | 8bda98a9671 |
15 | 46978788dd2 |
hex | 2546c7cc953 |
2561620625747 has 2 divisors, whose sum is σ = 2561620625748. Its totient is φ = 2561620625746.
The previous prime is 2561620625687. The next prime is 2561620625771. The reversal of 2561620625747 is 7475260261652.
2561620625747 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2561620625747 - 210 = 2561620624723 is a prime.
It is not a weakly prime, because it can be changed into another prime (2561620625777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280810312873 + 1280810312874.
It is an arithmetic number, because the mean of its divisors is an integer number (1280810312874).
Almost surely, 22561620625747 is an apocalyptic number.
2561620625747 is a deficient number, since it is larger than the sum of its proper divisors (1).
2561620625747 is an equidigital number, since it uses as much as digits as its factorization.
2561620625747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8467200, while the sum is 53.
The spelling of 2561620625747 in words is "two trillion, five hundred sixty-one billion, six hundred twenty million, six hundred twenty-five thousand, seven hundred forty-seven".
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