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2561983145153 is a prime number
BaseRepresentation
bin100101010010000010000…
…110000110010011000001
3100001220221000021120200022
4211102002012012103001
5313433420141121103
65240543034103225
7353045221264415
oct45220206062301
910056830246608
102561983145153
118a8592770683
12354642b7ab15
13157794c649a3
148c001ab4d45
154699a4e7138
hex254821864c1

2561983145153 has 2 divisors, whose sum is σ = 2561983145154. Its totient is φ = 2561983145152.

The previous prime is 2561983145087. The next prime is 2561983145203. The reversal of 2561983145153 is 3515413891652.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2232176438209 + 329806706944 = 1494047^2 + 574288^2 .

It is a cyclic number.

It is not a de Polignac number, because 2561983145153 - 214 = 2561983128769 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2561983145095 and 2561983145104.

It is not a weakly prime, because it can be changed into another prime (2561983145753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280991572576 + 1280991572577.

It is an arithmetic number, because the mean of its divisors is an integer number (1280991572577).

Almost surely, 22561983145153 is an apocalyptic number.

It is an amenable number.

2561983145153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2561983145153 is an equidigital number, since it uses as much as digits as its factorization.

2561983145153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3888000, while the sum is 53.

The spelling of 2561983145153 in words is "two trillion, five hundred sixty-one billion, nine hundred eighty-three million, one hundred forty-five thousand, one hundred fifty-three".