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256203431131 is a prime number
BaseRepresentation
bin1110111010011011101…
…0100001110011011011
3220111022020221210211211
43232212322201303123
513144201034244011
6313410452403551
724336650142544
oct3564672416333
9814266853754
10256203431131
119972318093a
12417a20165b7
131b2103438bb
14c5866574cb
1569e7737b21
hex3ba6ea1cdb

256203431131 has 2 divisors, whose sum is σ = 256203431132. Its totient is φ = 256203431130.

The previous prime is 256203431119. The next prime is 256203431137. The reversal of 256203431131 is 131134302652.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 256203431131 - 29 = 256203430619 is a prime.

It is a super-2 number, since 2×2562034311312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 256203431093 and 256203431102.

It is not a weakly prime, because it can be changed into another prime (256203431137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128101715565 + 128101715566.

It is an arithmetic number, because the mean of its divisors is an integer number (128101715566).

Almost surely, 2256203431131 is an apocalyptic number.

256203431131 is a deficient number, since it is larger than the sum of its proper divisors (1).

256203431131 is an equidigital number, since it uses as much as digits as its factorization.

256203431131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 256203431131 its reverse (131134302652), we get a palindrome (387337733783).

The spelling of 256203431131 in words is "two hundred fifty-six billion, two hundred three million, four hundred thirty-one thousand, one hundred thirty-one".