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256203431137 is a prime number
BaseRepresentation
bin1110111010011011101…
…0100001110011100001
3220111022020221210212001
43232212322201303201
513144201034244022
6313410452404001
724336650142553
oct3564672416341
9814266853761
10256203431137
1199723180945
12417a2016601
131b2103438c4
14c5866574d3
1569e7737b27
hex3ba6ea1ce1

256203431137 has 2 divisors, whose sum is σ = 256203431138. Its totient is φ = 256203431136.

The previous prime is 256203431131. The next prime is 256203431167. The reversal of 256203431137 is 731134302652.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 235078552801 + 21124878336 = 484849^2 + 145344^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-256203431137 is a prime.

It is a super-2 number, since 2×2562034311372 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 256203431096 and 256203431105.

It is not a weakly prime, because it can be changed into another prime (256203431131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128101715568 + 128101715569.

It is an arithmetic number, because the mean of its divisors is an integer number (128101715569).

Almost surely, 2256203431137 is an apocalyptic number.

It is an amenable number.

256203431137 is a deficient number, since it is larger than the sum of its proper divisors (1).

256203431137 is an equidigital number, since it uses as much as digits as its factorization.

256203431137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 37.

Adding to 256203431137 its reverse (731134302652), we get a palindrome (987337733789).

The spelling of 256203431137 in words is "two hundred fifty-six billion, two hundred three million, four hundred thirty-one thousand, one hundred thirty-seven".