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25622252534149 is a prime number
BaseRepresentation
bin1011101001101101001010…
…10000101011100110000101
310100201110111211111112202121
411310312211100223212011
511324243333122043044
6130254411134005541
75253101206035655
oct564664520534605
9110643454445677
1025622252534149
118189377648387
122a599206468b1
13113b22527646b
146481a33a4365
152e6760cd8984
hex174da542b985

25622252534149 has 2 divisors, whose sum is σ = 25622252534150. Its totient is φ = 25622252534148.

The previous prime is 25622252534141. The next prime is 25622252534183. The reversal of 25622252534149 is 94143525222652.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15371049471649 + 10251203062500 = 3920593^2 + 3201750^2 .

It is a cyclic number.

It is not a de Polignac number, because 25622252534149 - 23 = 25622252534141 is a prime.

It is a super-2 number, since 2×256222525341492 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25622252534096 and 25622252534105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25622252534141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12811126267074 + 12811126267075.

It is an arithmetic number, because the mean of its divisors is an integer number (12811126267075).

Almost surely, 225622252534149 is an apocalyptic number.

It is an amenable number.

25622252534149 is a deficient number, since it is larger than the sum of its proper divisors (1).

25622252534149 is an equidigital number, since it uses as much as digits as its factorization.

25622252534149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368000, while the sum is 52.

The spelling of 25622252534149 in words is "twenty-five trillion, six hundred twenty-two billion, two hundred fifty-two million, five hundred thirty-four thousand, one hundred forty-nine".