Base | Representation |
---|---|
bin | 1011101001110010100001… |
… | …11001001110000111000001 |
3 | 10100201201221111211212210102 |
4 | 11310321100321032013001 |
5 | 11324320232302041332 |
6 | 130300005000212145 |
7 | 5253232442455166 |
oct | 564712071160701 |
9 | 110651844755712 |
10 | 25625132065217 |
11 | 818a615006723 |
12 | 2a5a3a4a6a055 |
13 | 113b5939cb4b9 |
14 | 6483979ac06d |
15 | 2e687d9d3062 |
hex | 174e50e4e1c1 |
25625132065217 has 2 divisors, whose sum is σ = 25625132065218. Its totient is φ = 25625132065216.
The previous prime is 25625132065151. The next prime is 25625132065231. The reversal of 25625132065217 is 71256023152652.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22826617953841 + 2798514111376 = 4777721^2 + 1672876^2 .
It is a cyclic number.
It is not a de Polignac number, because 25625132065217 - 230 = 25624058323393 is a prime.
It is not a weakly prime, because it can be changed into another prime (25625132065277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12812566032608 + 12812566032609.
It is an arithmetic number, because the mean of its divisors is an integer number (12812566032609).
Almost surely, 225625132065217 is an apocalyptic number.
It is an amenable number.
25625132065217 is a deficient number, since it is larger than the sum of its proper divisors (1).
25625132065217 is an equidigital number, since it uses as much as digits as its factorization.
25625132065217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512000, while the sum is 47.
The spelling of 25625132065217 in words is "twenty-five trillion, six hundred twenty-five billion, one hundred thirty-two million, sixty-five thousand, two hundred seventeen".
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