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25630330345943 is a prime number
BaseRepresentation
bin1011101001111100001101…
…01111000101100111010111
310100202020100210022220101012
411310332012233011213113
511324411404032032233
6130302224453322435
75253505323226451
oct564760657054727
9110666323286335
1025630330345943
1181918423319a4
122a5b3b593641b
13113bc1196195b
1464872c1252d1
152e6a85054548
hex174f86bc59d7

25630330345943 has 2 divisors, whose sum is σ = 25630330345944. Its totient is φ = 25630330345942.

The previous prime is 25630330345897. The next prime is 25630330345957. The reversal of 25630330345943 is 34954303303652.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25630330345943 - 220 = 25630329297367 is a prime.

It is a super-3 number, since 3×256303303459433 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25630330345891 and 25630330345900.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25630330345993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12815165172971 + 12815165172972.

It is an arithmetic number, because the mean of its divisors is an integer number (12815165172972).

Almost surely, 225630330345943 is an apocalyptic number.

25630330345943 is a deficient number, since it is larger than the sum of its proper divisors (1).

25630330345943 is an equidigital number, since it uses as much as digits as its factorization.

25630330345943 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10497600, while the sum is 50.

The spelling of 25630330345943 in words is "twenty-five trillion, six hundred thirty billion, three hundred thirty million, three hundred forty-five thousand, nine hundred forty-three".