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25655041269391 is a prime number
BaseRepresentation
bin1011101010101010001111…
…00111110001111010001111
310100211121010221021212201011
411311111013213301322033
511330313011031110031
6130321432510230051
75255341560505162
oct565250747617217
9110747127255634
1025655041269391
1181a1272a75486
122a641514b5327
13114134c323351
146499d3d3dad9
152e752e6746b1
hex1755479f1e8f

25655041269391 has 2 divisors, whose sum is σ = 25655041269392. Its totient is φ = 25655041269390.

The previous prime is 25655041269313. The next prime is 25655041269397. The reversal of 25655041269391 is 19396214055652.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25655041269391 - 215 = 25655041236623 is a prime.

It is a super-2 number, since 2×256550412693912 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25655041269397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12827520634695 + 12827520634696.

It is an arithmetic number, because the mean of its divisors is an integer number (12827520634696).

Almost surely, 225655041269391 is an apocalyptic number.

25655041269391 is a deficient number, since it is larger than the sum of its proper divisors (1).

25655041269391 is an equidigital number, since it uses as much as digits as its factorization.

25655041269391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496000, while the sum is 58.

The spelling of 25655041269391 in words is "twenty-five trillion, six hundred fifty-five billion, forty-one million, two hundred sixty-nine thousand, three hundred ninety-one".