Base | Representation |
---|---|
bin | 10111111001110100… |
… | …011100011100001001 |
3 | 2110020201022112122122 |
4 | 113321310130130021 |
5 | 410031011024431 |
6 | 15442453501025 |
7 | 1566013226441 |
oct | 277164343411 |
9 | 73221275578 |
10 | 25666111241 |
11 | a98093a291 |
12 | 4b83641775 |
13 | 256053b894 |
14 | 1356a1d121 |
15 | a033eda7b |
hex | 5f9d1c709 |
25666111241 has 2 divisors, whose sum is σ = 25666111242. Its totient is φ = 25666111240.
The previous prime is 25666111189. The next prime is 25666111243. The reversal of 25666111241 is 14211166652.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25399115641 + 266995600 = 159371^2 + 16340^2 .
It is a cyclic number.
It is not a de Polignac number, because 25666111241 - 234 = 8486242057 is a prime.
Together with 25666111243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (25666111243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12833055620 + 12833055621.
It is an arithmetic number, because the mean of its divisors is an integer number (12833055621).
Almost surely, 225666111241 is an apocalyptic number.
It is an amenable number.
25666111241 is a deficient number, since it is larger than the sum of its proper divisors (1).
25666111241 is an equidigital number, since it uses as much as digits as its factorization.
25666111241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 17280, while the sum is 35.
Adding to 25666111241 its reverse (14211166652), we get a palindrome (39877277893).
The spelling of 25666111241 in words is "twenty-five billion, six hundred sixty-six million, one hundred eleven thousand, two hundred forty-one".
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