Base | Representation |
---|---|
bin | 1110111101110100101… |
… | …1100101000111010111 |
3 | 220120122201002221021211 |
4 | 3233131023211013113 |
5 | 13203032122331212 |
6 | 314041054322251 |
7 | 24401343561613 |
oct | 3573513450727 |
9 | 816581087254 |
10 | 257113870807 |
11 | 9a050093722 |
12 | 419b6ab9387 |
13 | 1b326b53cc1 |
14 | c631530343 |
15 | 6a4c6279a7 |
hex | 3bdd2e51d7 |
257113870807 has 2 divisors, whose sum is σ = 257113870808. Its totient is φ = 257113870806.
The previous prime is 257113870771. The next prime is 257113870813. The reversal of 257113870807 is 708078311752.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 257113870807 - 215 = 257113838039 is a prime.
It is a super-2 number, since 2×2571138708072 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (257113870837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 128556935403 + 128556935404.
It is an arithmetic number, because the mean of its divisors is an integer number (128556935404).
Almost surely, 2257113870807 is an apocalyptic number.
257113870807 is a deficient number, since it is larger than the sum of its proper divisors (1).
257113870807 is an equidigital number, since it uses as much as digits as its factorization.
257113870807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 658560, while the sum is 49.
The spelling of 257113870807 in words is "two hundred fifty-seven billion, one hundred thirteen million, eight hundred seventy thousand, eight hundred seven".
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