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25713331550717 is a prime number
BaseRepresentation
bin1011101100010110110011…
…11111100011100111111101
310101001011121021201222100112
411312023121333203213331
511332241400334110332
6130404312541235405
75262504216642266
oct566133177434775
9111034537658315
1025713331550717
118213a653515a8
122a734ba862b65
1311469ab7b0485
1464c7636db96d
152e8ce1c53db2
hex1762d9fe39fd

25713331550717 has 2 divisors, whose sum is σ = 25713331550718. Its totient is φ = 25713331550716.

The previous prime is 25713331550663. The next prime is 25713331550743. The reversal of 25713331550717 is 71705513331752.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18233702768836 + 7479628781881 = 4270094^2 + 2734891^2 .

It is a cyclic number.

It is not a de Polignac number, because 25713331550717 - 212 = 25713331546621 is a prime.

It is a super-2 number, since 2×257133315507172 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25713331550617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12856665775358 + 12856665775359.

It is an arithmetic number, because the mean of its divisors is an integer number (12856665775359).

Almost surely, 225713331550717 is an apocalyptic number.

It is an amenable number.

25713331550717 is a deficient number, since it is larger than the sum of its proper divisors (1).

25713331550717 is an equidigital number, since it uses as much as digits as its factorization.

25713331550717 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2315250, while the sum is 50.

The spelling of 25713331550717 in words is "twenty-five trillion, seven hundred thirteen billion, three hundred thirty-one million, five hundred fifty thousand, seven hundred seventeen".