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25718405143 is a prime number
BaseRepresentation
bin10111111100111011…
…111011100000010111
32110101100201100101211
4113330323323200113
5410132402431033
615452002402251
71600216560004
oct277473734027
973340640354
1025718405143
11a9a8407492
124b99060387
13256b31b112
14135d9528ab
15a07ccd2cd
hex5fcefb817

25718405143 has 2 divisors, whose sum is σ = 25718405144. Its totient is φ = 25718405142.

The previous prime is 25718405117. The next prime is 25718405159. The reversal of 25718405143 is 34150481752.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25718405143 is a prime.

It is a super-2 number, since 2×257184051432 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25718405096 and 25718405105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25718405543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12859202571 + 12859202572.

It is an arithmetic number, because the mean of its divisors is an integer number (12859202572).

Almost surely, 225718405143 is an apocalyptic number.

25718405143 is a deficient number, since it is larger than the sum of its proper divisors (1).

25718405143 is an equidigital number, since it uses as much as digits as its factorization.

25718405143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 134400, while the sum is 40.

Adding to 25718405143 its reverse (34150481752), we get a palindrome (59868886895).

The spelling of 25718405143 in words is "twenty-five billion, seven hundred eighteen million, four hundred five thousand, one hundred forty-three".