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2572260032437 is a prime number
BaseRepresentation
bin100101011011100110101…
…001010011111110110101
3100002220110020001112202021
4211123212221103332311
5314120442032014222
65245402511313141
7353561000344054
oct45334651237665
910086406045667
102572260032437
11901986803157
1235663081b7b1
13158742119a94
148c6d891239b
1546d9c84aac7
hex256e6a53fb5

2572260032437 has 2 divisors, whose sum is σ = 2572260032438. Its totient is φ = 2572260032436.

The previous prime is 2572260032371. The next prime is 2572260032479. The reversal of 2572260032437 is 7342300622752.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1874076122961 + 698183909476 = 1368969^2 + 835574^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2572260032437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2572260032393 and 2572260032402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2572260032737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1286130016218 + 1286130016219.

It is an arithmetic number, because the mean of its divisors is an integer number (1286130016219).

Almost surely, 22572260032437 is an apocalyptic number.

It is an amenable number.

2572260032437 is a deficient number, since it is larger than the sum of its proper divisors (1).

2572260032437 is an equidigital number, since it uses as much as digits as its factorization.

2572260032437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 846720, while the sum is 43.

The spelling of 2572260032437 in words is "two trillion, five hundred seventy-two billion, two hundred sixty million, thirty-two thousand, four hundred thirty-seven".