2573983993413 has 32 divisors (see below), whose sum is σ = 4054911803392. Its totient is φ = 1421247643200.

The previous prime is 2573983993411. The next prime is 2573983993423. The reversal of 2573983993413 is 3143993893752.

It is not a de Polignac number, because 2573983993413 - 2¹ = 2573983993411 is a prime.

It is a super-4 number, since 4×2573983993413⁴ (a number of 51 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2573983993411) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2560531 + ... + 3421152.

It is an arithmetic number, because the mean of its divisors is an integer number (126715993856).

Almost surely, 2^{2573983993413} is an apocalyptic number.

It is an amenable number.

2573983993413 is a deficient number, since it is larger than the sum of its proper divisors (1480927809979).

2573983993413 is a wasteful number, since it uses less digits than its factorization.

2573983993413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5982385.

The product of its digits is 132269760, while the sum is 66.

The spelling of 2573983993413 in words is "two trillion, five hundred seventy-three billion, nine hundred eighty-three million, nine hundred ninety-three thousand, four hundred thirteen".