Search a number
-
+
25748406913 is a prime number
BaseRepresentation
bin10111111110101110…
…011000001010000001
32110110110011121002111
4113332232120022001
5410213043010123
615454553415321
71601032563505
oct277656301201
973413147074
1025748406913
11aa13339239
124ba710a541
1325745c3b48
141363922305
15a0a75790d
hex5feb98281

25748406913 has 2 divisors, whose sum is σ = 25748406914. Its totient is φ = 25748406912.

The previous prime is 25748406877. The next prime is 25748406961. The reversal of 25748406913 is 31960484752.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24003924624 + 1744482289 = 154932^2 + 41767^2 .

It is a cyclic number.

It is not a de Polignac number, because 25748406913 - 213 = 25748398721 is a prime.

It is not a weakly prime, because it can be changed into another prime (25548406913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12874203456 + 12874203457.

It is an arithmetic number, because the mean of its divisors is an integer number (12874203457).

It is a 1-persistent number, because it is pandigital, but 2⋅25748406913 = 51496813826 is not.

Almost surely, 225748406913 is an apocalyptic number.

It is an amenable number.

25748406913 is a deficient number, since it is larger than the sum of its proper divisors (1).

25748406913 is an equidigital number, since it uses as much as digits as its factorization.

25748406913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 49.

The spelling of 25748406913 in words is "twenty-five billion, seven hundred forty-eight million, four hundred six thousand, nine hundred thirteen".