Base | Representation |
---|---|
bin | 100101011110001100000… |
… | …010101001010101000101 |
3 | 100010011121121111010210211 |
4 | 211132030002221111011 |
5 | 314142132414222432 |
6 | 5250542114515421 |
7 | 354016523425111 |
oct | 45361402512505 |
9 | 10104547433724 |
10 | 2575034914117 |
11 | 9030800948a6 |
12 | 357085b95b71 |
13 | 158a94c90cc3 |
14 | 8c8bd278741 |
15 | 46eb1272d47 |
hex | 2578c0a9545 |
2575034914117 has 2 divisors, whose sum is σ = 2575034914118. Its totient is φ = 2575034914116.
The previous prime is 2575034914091. The next prime is 2575034914189. The reversal of 2575034914117 is 7114194305752.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2448095200321 + 126939713796 = 1564639^2 + 356286^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2575034914117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2575034954117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1287517457058 + 1287517457059.
It is an arithmetic number, because the mean of its divisors is an integer number (1287517457059).
Almost surely, 22575034914117 is an apocalyptic number.
It is an amenable number.
2575034914117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2575034914117 is an equidigital number, since it uses as much as digits as its factorization.
2575034914117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1058400, while the sum is 49.
The spelling of 2575034914117 in words is "two trillion, five hundred seventy-five billion, thirty-four million, nine hundred fourteen thousand, one hundred seventeen".
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