Base | Representation |
---|---|
bin | 10111111111011111… |
… | …111110000001001101 |
3 | 2110111100122001221011 |
4 | 113333133332001031 |
5 | 410224410011203 |
6 | 15500140205221 |
7 | 1601251230004 |
oct | 277737760115 |
9 | 73440561834 |
10 | 25761407053 |
11 | aa1a708458 |
12 | 4bab539811 |
13 | 25771c6135 |
14 | 1365547c3b |
15 | a0b97476d |
hex | 5ff7fe04d |
25761407053 has 2 divisors, whose sum is σ = 25761407054. Its totient is φ = 25761407052.
The previous prime is 25761407047. The next prime is 25761407057. The reversal of 25761407053 is 35070416752.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21037181764 + 4724225289 = 145042^2 + 68733^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25761407053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25761406997 and 25761407015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25761407057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12880703526 + 12880703527.
It is an arithmetic number, because the mean of its divisors is an integer number (12880703527).
Almost surely, 225761407053 is an apocalyptic number.
It is an amenable number.
25761407053 is a deficient number, since it is larger than the sum of its proper divisors (1).
25761407053 is an equidigital number, since it uses as much as digits as its factorization.
25761407053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 176400, while the sum is 40.
The spelling of 25761407053 in words is "twenty-five billion, seven hundred sixty-one million, four hundred seven thousand, fifty-three".
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