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258032047811 is a prime number
BaseRepresentation
bin1111000001001111101…
…0001001011011000011
3220200000200211011100112
43300103322021123003
513211422201012221
6314312134141535
724433163134526
oct3602372113303
9820020734315
10258032047811
119a48140069a
12420124b18ab
131b4421430c5
14c6bb45cbbd
156aa304515b
hex3c13e896c3

258032047811 has 2 divisors, whose sum is σ = 258032047812. Its totient is φ = 258032047810.

The previous prime is 258032047807. The next prime is 258032047813. The reversal of 258032047811 is 118740230852.

258032047811 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 258032047811 - 22 = 258032047807 is a prime.

Together with 258032047813, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (258032047813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129016023905 + 129016023906.

It is an arithmetic number, because the mean of its divisors is an integer number (129016023906).

Almost surely, 2258032047811 is an apocalyptic number.

258032047811 is a deficient number, since it is larger than the sum of its proper divisors (1).

258032047811 is an equidigital number, since it uses as much as digits as its factorization.

258032047811 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 107520, while the sum is 41.

The spelling of 258032047811 in words is "two hundred fifty-eight billion, thirty-two million, forty-seven thousand, eight hundred eleven".