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25804703874413 is a prime number
BaseRepresentation
bin1011101111000001000000…
…01101010011110101101101
310101100220110011212221200102
411313200200031103311231
511340241013142440123
6130514303423240445
75302220421611462
oct567404015236555
9111326404787612
1025804703874413
118249793678802
122a8915b149125
1311524b0a10ab9
14652d50985669
152eb38d80a028
hex177820353d6d

25804703874413 has 2 divisors, whose sum is σ = 25804703874414. Its totient is φ = 25804703874412.

The previous prime is 25804703874373. The next prime is 25804703874529. The reversal of 25804703874413 is 31447830740852.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25104138222409 + 700565652004 = 5010403^2 + 836998^2 .

It is a cyclic number.

It is not a de Polignac number, because 25804703874413 - 212 = 25804703870317 is a prime.

It is a super-2 number, since 2×258047038744132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25804703774413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12902351937206 + 12902351937207.

It is an arithmetic number, because the mean of its divisors is an integer number (12902351937207).

Almost surely, 225804703874413 is an apocalyptic number.

It is an amenable number.

25804703874413 is a deficient number, since it is larger than the sum of its proper divisors (1).

25804703874413 is an equidigital number, since it uses as much as digits as its factorization.

25804703874413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18063360, while the sum is 56.

The spelling of 25804703874413 in words is "twenty-five trillion, eight hundred four billion, seven hundred three million, eight hundred seventy-four thousand, four hundred thirteen".