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25806497 is a prime number
BaseRepresentation
bin110001001110…
…0011010100001
31210120002212012
41202130122201
523101301442
62321042305
7432231413
oct142343241
953502765
1025806497
1113626892
128786395
135467322
1435da9b3
1523eb582
hex189c6a1

25806497 has 2 divisors, whose sum is σ = 25806498. Its totient is φ = 25806496.

The previous prime is 25806479. The next prime is 25806499. The reversal of 25806497 is 79460852.

25806497 is nontrivially palindromic in base 8.

Together with previous prime (25806479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24364096 + 1442401 = 4936^2 + 1201^2 .

It is a cyclic number.

It is not a de Polignac number, because 25806497 - 212 = 25802401 is a prime.

It is a super-2 number, since 2×258064972 = 1331950574822018, which contains 22 as substring.

Together with 25806499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (25806499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12903248 + 12903249.

It is an arithmetic number, because the mean of its divisors is an integer number (12903249).

Almost surely, 225806497 is an apocalyptic number.

It is an amenable number.

25806497 is a deficient number, since it is larger than the sum of its proper divisors (1).

25806497 is an equidigital number, since it uses as much as digits as its factorization.

25806497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 41.

The square root of 25806497 is about 5080.0095472351. The cubic root of 25806497 is about 295.5128377205.

The spelling of 25806497 in words is "twenty-five million, eight hundred six thousand, four hundred ninety-seven".