Base | Representation |
---|---|
bin | 1111000010011110011… |
… | …1110101001000000001 |
3 | 220200212202011121220002 |
4 | 3300213213311020001 |
5 | 13213111333243101 |
6 | 314405031125345 |
7 | 24444320324612 |
oct | 3604747651001 |
9 | 820782147802 |
10 | 258362790401 |
11 | 9a631072481 |
12 | 420a5213855 |
13 | 1b495815b91 |
14 | c70d355c09 |
15 | 6ac20c7d6b |
hex | 3c279f5201 |
258362790401 has 2 divisors, whose sum is σ = 258362790402. Its totient is φ = 258362790400.
The previous prime is 258362790379. The next prime is 258362790437. The reversal of 258362790401 is 104097263852.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 258189999376 + 172791025 = 508124^2 + 13145^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-258362790401 is a prime.
It is not a weakly prime, because it can be changed into another prime (258362793401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129181395200 + 129181395201.
It is an arithmetic number, because the mean of its divisors is an integer number (129181395201).
It is a 1-persistent number, because it is pandigital, but 2⋅258362790401 = 516725580802 is not.
Almost surely, 2258362790401 is an apocalyptic number.
It is an amenable number.
258362790401 is a deficient number, since it is larger than the sum of its proper divisors (1).
258362790401 is an equidigital number, since it uses as much as digits as its factorization.
258362790401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 47.
The spelling of 258362790401 in words is "two hundred fifty-eight billion, three hundred sixty-two million, seven hundred ninety thousand, four hundred one".
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