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258411589061 is a prime number
BaseRepresentation
bin1111000010101010000…
…1111110110111000101
3220201000010222212001212
43300222201332313011
513213211331322221
6314413533101205
724445452160013
oct3605241766705
9821003885055
10258411589061
119a65667264a
12420b9627805
131b4a2970522
14c715a198b3
156ac6516b5b
hex3c2a87edc5

258411589061 has 2 divisors, whose sum is σ = 258411589062. Its totient is φ = 258411589060.

The previous prime is 258411588947. The next prime is 258411589127. The reversal of 258411589061 is 160985114852.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 194630086561 + 63781502500 = 441169^2 + 252550^2 .

It is a cyclic number.

It is not a de Polignac number, because 258411589061 - 214 = 258411572677 is a prime.

It is a super-3 number, since 3×2584115890613 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (258411549061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 129205794530 + 129205794531.

It is an arithmetic number, because the mean of its divisors is an integer number (129205794531).

Almost surely, 2258411589061 is an apocalyptic number.

It is an amenable number.

258411589061 is a deficient number, since it is larger than the sum of its proper divisors (1).

258411589061 is an equidigital number, since it uses as much as digits as its factorization.

258411589061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 50.

The spelling of 258411589061 in words is "two hundred fifty-eight billion, four hundred eleven million, five hundred eighty-nine thousand, sixty-one".