Base | Representation |
---|---|
bin | 1001101000011110… |
… | …0101110110111101 |
3 | 20200012102012222121 |
4 | 2122013211312331 |
5 | 20243413300331 |
6 | 1104324042541 |
7 | 121034633365 |
oct | 23207456675 |
9 | 6605365877 |
10 | 2585681341 |
11 | 1107605731 |
12 | 601b33451 |
13 | 3228cb779 |
14 | 1a75959a5 |
15 | 102002c11 |
hex | 9a1e5dbd |
2585681341 has 2 divisors, whose sum is σ = 2585681342. Its totient is φ = 2585681340.
The previous prime is 2585681333. The next prime is 2585681347. The reversal of 2585681341 is 1431865852.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1431108900 + 1154572441 = 37830^2 + 33979^2 .
It is a cyclic number.
It is not a de Polignac number, because 2585681341 - 23 = 2585681333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2585681347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1292840670 + 1292840671.
It is an arithmetic number, because the mean of its divisors is an integer number (1292840671).
Almost surely, 22585681341 is an apocalyptic number.
It is an amenable number.
2585681341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2585681341 is an equidigital number, since it uses as much as digits as its factorization.
2585681341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 230400, while the sum is 43.
The square root of 2585681341 is about 50849.5952884583. The cubic root of 2585681341 is about 1372.5399700150.
The spelling of 2585681341 in words is "two billion, five hundred eighty-five million, six hundred eighty-one thousand, three hundred forty-one".
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