Base | Representation |
---|---|
bin | 1001101001100001… |
… | …1000110011101101 |
3 | 20200111200220202101 |
4 | 2122120120303231 |
5 | 20301030144313 |
6 | 1105002255101 |
7 | 121120232164 |
oct | 23230306355 |
9 | 6614626671 |
10 | 2590084333 |
11 | 110a042771 |
12 | 6034b7491 |
13 | 3237b08a5 |
14 | 1a7dc03db |
15 | 1025c25dd |
hex | 9a618ced |
2590084333 has 2 divisors, whose sum is σ = 2590084334. Its totient is φ = 2590084332.
The previous prime is 2590084309. The next prime is 2590084361. The reversal of 2590084333 is 3334800952.
2590084333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2513819044 + 76265289 = 50138^2 + 8733^2 .
It is a cyclic number.
It is not a de Polignac number, because 2590084333 - 225 = 2556529901 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2590084292 and 2590084301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2590084373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1295042166 + 1295042167.
It is an arithmetic number, because the mean of its divisors is an integer number (1295042167).
Almost surely, 22590084333 is an apocalyptic number.
It is an amenable number.
2590084333 is a deficient number, since it is larger than the sum of its proper divisors (1).
2590084333 is an equidigital number, since it uses as much as digits as its factorization.
2590084333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 37.
The square root of 2590084333 is about 50892.8711412512. The cubic root of 2590084333 is about 1373.3185985094.
The spelling of 2590084333 in words is "two billion, five hundred ninety million, eighty-four thousand, three hundred thirty-three".
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