Base | Representation |
---|---|
bin | 11000001101001001… |
… | …010101011000001111 |
3 | 2111002022102210201021 |
4 | 120031021111120033 |
5 | 411212012320242 |
6 | 15534555255011 |
7 | 1610031240061 |
oct | 301511253017 |
9 | 74068383637 |
10 | 25990354447 |
11 | 10027971a82 |
12 | 505414a467 |
13 | 25b2777275 |
14 | 1387b03731 |
15 | a21aeab67 |
hex | 60d25560f |
25990354447 has 2 divisors, whose sum is σ = 25990354448. Its totient is φ = 25990354446.
The previous prime is 25990354417. The next prime is 25990354459. The reversal of 25990354447 is 74445309952.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25990354447 - 27 = 25990354319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25990354394 and 25990354403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25990354417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12995177223 + 12995177224.
It is an arithmetic number, because the mean of its divisors is an integer number (12995177224).
Almost surely, 225990354447 is an apocalyptic number.
25990354447 is a deficient number, since it is larger than the sum of its proper divisors (1).
25990354447 is an equidigital number, since it uses as much as digits as its factorization.
25990354447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5443200, while the sum is 52.
The spelling of 25990354447 in words is "twenty-five billion, nine hundred ninety million, three hundred fifty-four thousand, four hundred forty-seven".
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