26042327537 has 2 divisors, whose sum is σ = 26042327538. Its totient is φ = 26042327536.

The previous prime is 26042327513. The next prime is 26042327539. The reversal of 26042327537 is 73572324062.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22878377536 + 3163950001 = 151256^2 + 56249^2 .

It is a cyclic number.

It is not a de Polignac number, because 26042327537 - 2⁸ = 26042327281 is a prime.

Together with 26042327539, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 26042327494 and 26042327503.

It is not a weakly prime, because it can be changed into another prime (26042327539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13021163768 + 13021163769.

It is an arithmetic number, because the mean of its divisors is an integer number (13021163769).

Almost surely, 2^26042327537 is an apocalyptic number.

It is an amenable number.

26042327537 is a deficient number, since it is larger than the sum of its proper divisors (1).

26042327537 is an equidigital number, since it uses as much as digits as its factorization.

26042327537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 423360, while the sum is 41.

The spelling of 26042327537 in words is "twenty-six billion, forty-two million, three hundred twenty-seven thousand, five hundred thirty-seven".