Base | Representation |
---|---|
bin | 1011110110010010010010… |
… | …11001100110011100111011 |
3 | 10102020210020010010122121221 |
4 | 11323021021121212130323 |
5 | 11403334110241043103 |
6 | 131225135023012511 |
7 | 5326242605654311 |
oct | 573111131463473 |
9 | 112223203118557 |
10 | 26054503065403 |
11 | 833571a81719a |
12 | 2b0965443a137 |
13 | 116cc102c1397 |
14 | 66108a8440b1 |
15 | 302b0dbaa1bd |
hex | 17b24966673b |
26054503065403 has 2 divisors, whose sum is σ = 26054503065404. Its totient is φ = 26054503065402.
The previous prime is 26054503065401. The next prime is 26054503065473. The reversal of 26054503065403 is 30456030545062.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 26054503065403 - 21 = 26054503065401 is a prime.
Together with 26054503065401, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 26054503065403.
It is not a weakly prime, because it can be changed into another prime (26054503065401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13027251532701 + 13027251532702.
It is an arithmetic number, because the mean of its divisors is an integer number (13027251532702).
Almost surely, 226054503065403 is an apocalyptic number.
26054503065403 is a deficient number, since it is larger than the sum of its proper divisors (1).
26054503065403 is an equidigital number, since it uses as much as digits as its factorization.
26054503065403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296000, while the sum is 43.
The spelling of 26054503065403 in words is "twenty-six trillion, fifty-four billion, five hundred three million, sixty-five thousand, four hundred three".
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