261114433 has 2 divisors, whose sum is σ = 261114434. Its totient is φ = 261114432.

The previous prime is 261114379. The next prime is 261114437. The reversal of 261114433 is 334411162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 193989184 + 67125249 = 13928^2 + 8193^2 .

It is a cyclic number.

It is not a de Polignac number, because 261114433 - 2¹⁷ = 260983361 is a prime.

It is a super-2 number, since 2×261114433² = 136361494241822978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 261114398 and 261114407.

It is not a weakly prime, because it can be changed into another prime (261114437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130557216 + 130557217.

It is an arithmetic number, because the mean of its divisors is an integer number (130557217).

Almost surely, 2^261114433 is an apocalyptic number.

It is an amenable number.

261114433 is a deficient number, since it is larger than the sum of its proper divisors (1).

261114433 is an equidigital number, since it uses as much as digits as its factorization.

261114433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

The square root of 261114433 is about 16159.0356457308. The cubic root of 261114433 is about 639.1610369313.

Adding to 261114433 its reverse (334411162), we get a palindrome (595525595).

The spelling of 261114433 in words is "two hundred sixty-one million, one hundred fourteen thousand, four hundred thirty-three".