Base | Representation |
---|---|
bin | 1111001100110000101… |
… | …0001111000001100111 |
3 | 220222000010111122212012 |
4 | 3303030022033001213 |
5 | 13234240024212212 |
6 | 315543001544435 |
7 | 24602610124355 |
oct | 3631412170147 |
9 | 828003448765 |
10 | 261123272807 |
11 | a08183097a1 |
12 | 427357a511b |
13 | 1b8156b8017 |
14 | c8d1c107d5 |
15 | 6bd4608922 |
hex | 3ccc28f067 |
261123272807 has 2 divisors, whose sum is σ = 261123272808. Its totient is φ = 261123272806.
The previous prime is 261123272803. The next prime is 261123272887. The reversal of 261123272807 is 708272321162.
261123272807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 261123272807 - 22 = 261123272803 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (261123272801) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 130561636403 + 130561636404.
It is an arithmetic number, because the mean of its divisors is an integer number (130561636404).
Almost surely, 2261123272807 is an apocalyptic number.
261123272807 is a deficient number, since it is larger than the sum of its proper divisors (1).
261123272807 is an equidigital number, since it uses as much as digits as its factorization.
261123272807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112896, while the sum is 41.
Adding to 261123272807 its reverse (708272321162), we get a palindrome (969395593969).
The spelling of 261123272807 in words is "two hundred sixty-one billion, one hundred twenty-three million, two hundred seventy-two thousand, eight hundred seven".
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