Base | Representation |
---|---|
bin | 11000010100011101… |
… | …101110011100100101 |
3 | 2111101212110222112111 |
4 | 120110131232130211 |
5 | 411434430444032 |
6 | 15555103121021 |
7 | 1613052014002 |
oct | 302435563445 |
9 | 74355428474 |
10 | 26113140517 |
11 | 10090206a72 |
12 | 50892a3171 |
13 | 2602038349 |
14 | 139a1468a9 |
15 | a2c7a1c47 |
hex | 61476e725 |
26113140517 has 2 divisors, whose sum is σ = 26113140518. Its totient is φ = 26113140516.
The previous prime is 26113140503. The next prime is 26113140539. The reversal of 26113140517 is 71504131162.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22358024676 + 3755115841 = 149526^2 + 61279^2 .
It is a cyclic number.
It is not a de Polignac number, because 26113140517 - 215 = 26113107749 is a prime.
It is a super-2 number, since 2×261131405172 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26113140587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13056570258 + 13056570259.
It is an arithmetic number, because the mean of its divisors is an integer number (13056570259).
Almost surely, 226113140517 is an apocalyptic number.
It is an amenable number.
26113140517 is a deficient number, since it is larger than the sum of its proper divisors (1).
26113140517 is an equidigital number, since it uses as much as digits as its factorization.
26113140517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 26113140517 its reverse (71504131162), we get a palindrome (97617271679).
The spelling of 26113140517 in words is "twenty-six billion, one hundred thirteen million, one hundred forty thousand, five hundred seventeen".
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