Search a number
-
+
26113837 is a prime number
BaseRepresentation
bin110001110011…
…1011100101101
31211010201110011
41203213130231
523141120322
62331413221
7434651431
oct143473455
954121404
1026113837
1113816792
1288b4211
135544199
14367a9c1
15245c677
hex18e772d

26113837 has 2 divisors, whose sum is σ = 26113838. Its totient is φ = 26113836.

The previous prime is 26113817. The next prime is 26113849. The reversal of 26113837 is 73831162.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26020201 + 93636 = 5101^2 + 306^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-26113837 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 26113799 and 26113808.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (26113807) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13056918 + 13056919.

It is an arithmetic number, because the mean of its divisors is an integer number (13056919).

Almost surely, 226113837 is an apocalyptic number.

It is an amenable number.

26113837 is a deficient number, since it is larger than the sum of its proper divisors (1).

26113837 is an equidigital number, since it uses as much as digits as its factorization.

26113837 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048, while the sum is 31.

The square root of 26113837 is about 5110.1699580347. The cubic root of 26113837 is about 296.6813384712.

Adding to 26113837 its reverse (73831162), we get a palindrome (99944999).

The spelling of 26113837 in words is "twenty-six million, one hundred thirteen thousand, eight hundred thirty-seven".