Base | Representation |
---|---|
bin | 11000010100101001… |
… | …010011010001011111 |
3 | 2111102002012010222122 |
4 | 120110221103101133 |
5 | 411441220044233 |
6 | 15555252133155 |
7 | 1613116552505 |
oct | 302451232137 |
9 | 74362163878 |
10 | 26116174943 |
11 | 10091999861 |
12 | 508a3071bb |
13 | 260285b571 |
14 | 139a6d6675 |
15 | a2cba0d98 |
hex | 614a5345f |
26116174943 has 2 divisors, whose sum is σ = 26116174944. Its totient is φ = 26116174942.
The previous prime is 26116174919. The next prime is 26116174961. The reversal of 26116174943 is 34947161162.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26116174943 - 216 = 26116109407 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 26116174894 and 26116174903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26116174913) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13058087471 + 13058087472.
It is an arithmetic number, because the mean of its divisors is an integer number (13058087472).
Almost surely, 226116174943 is an apocalyptic number.
26116174943 is a deficient number, since it is larger than the sum of its proper divisors (1).
26116174943 is an equidigital number, since it uses as much as digits as its factorization.
26116174943 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 217728, while the sum is 44.
The spelling of 26116174943 in words is "twenty-six billion, one hundred sixteen million, one hundred seventy-four thousand, nine hundred forty-three".
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