Base | Representation |
---|---|
bin | 100110001010110111100… |
… | …110101110100001100101 |
3 | 100021202110002220000121012 |
4 | 212022313212232201211 |
5 | 320433411132330000 |
6 | 5324554440432005 |
7 | 360335433544655 |
oct | 46126746564145 |
9 | 10252402800535 |
10 | 2623010433125 |
11 | 92145a00a365 |
12 | 364434a78605 |
13 | 16046c494784 |
14 | 90d50b7a365 |
15 | 4836d01b735 |
hex | 262b79ae865 |
2623010433125 has 40 divisors (see below), whose sum is σ = 3538162425600. Its totient is φ = 1937960024000.
The previous prime is 2623010433101. The next prime is 2623010433163. The reversal of 2623010433125 is 5213340103262.
It is not a de Polignac number, because 2623010433125 - 222 = 2623006238821 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2623010433091 and 2623010433100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2729165 + ... + 3562914.
It is an arithmetic number, because the mean of its divisors is an integer number (88454060640).
Almost surely, 22623010433125 is an apocalyptic number.
2623010433125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
2623010433125 is a deficient number, since it is larger than the sum of its proper divisors (915151992475).
2623010433125 is an equidigital number, since it uses as much as digits as its factorization.
2623010433125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6292151 (or 6292136 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 2623010433125 its reverse (5213340103262), we get a palindrome (7836350536387).
The spelling of 2623010433125 in words is "two trillion, six hundred twenty-three billion, ten million, four hundred thirty-three thousand, one hundred twenty-five".
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