2632046311331 has 2 divisors, whose sum is σ = 2632046311332. Its totient is φ = 2632046311330.

The previous prime is 2632046311273. The next prime is 2632046311333. The reversal of 2632046311331 is 1331136402362.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2632046311331 - 2³⁴ = 2614866442147 is a prime.

It is a super-2 number, since 2×2632046311331² (a number of 26 digits) contains 22 as substring.

Together with 2632046311333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2632046311291 and 2632046311300.

It is not a weakly prime, because it can be changed into another prime (2632046311333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1316023155665 + 1316023155666.

It is an arithmetic number, because the mean of its divisors is an integer number (1316023155666).

Almost surely, 2^{2632046311331} is an apocalyptic number.

2632046311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

2632046311331 is an equidigital number, since it uses as much as digits as its factorization.

2632046311331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 35.

The spelling of 2632046311331 in words is "two trillion, six hundred thirty-two billion, forty-six million, three hundred eleven thousand, three hundred thirty-one".