Base | Representation |
---|---|
bin | 11000100010011100… |
… | …110001000100010011 |
3 | 2112000012222101212012 |
4 | 120202130301010103 |
5 | 412430012121011 |
6 | 20034244053135 |
7 | 1621631231234 |
oct | 304234610423 |
9 | 75005871765 |
10 | 26347770131 |
11 | 101a06a1741 |
12 | 51339941ab |
13 | 263b828937 |
14 | 13bd38108b |
15 | a4319ba8b |
hex | 622731113 |
26347770131 has 2 divisors, whose sum is σ = 26347770132. Its totient is φ = 26347770130.
The previous prime is 26347770121. The next prime is 26347770133. The reversal of 26347770131 is 13107774362.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26347770131 - 26 = 26347770067 is a prime.
It is a super-2 number, since 2×263477701312 (a number of 22 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 26347770133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (26347770133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13173885065 + 13173885066.
It is an arithmetic number, because the mean of its divisors is an integer number (13173885066).
Almost surely, 226347770131 is an apocalyptic number.
26347770131 is a deficient number, since it is larger than the sum of its proper divisors (1).
26347770131 is an equidigital number, since it uses as much as digits as its factorization.
26347770131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 148176, while the sum is 41.
The spelling of 26347770131 in words is "twenty-six billion, three hundred forty-seven million, seven hundred seventy thousand, one hundred thirty-one".
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