Base | Representation |
---|---|
bin | 11111011110100… |
… | …10000101111001 |
3 | 200101212021202221 |
4 | 33233102011321 |
5 | 1020044144423 |
6 | 42111324041 |
7 | 6354262102 |
oct | 1757220571 |
9 | 611767687 |
10 | 264053113 |
11 | 126062015 |
12 | 74520621 |
13 | 4292305c |
14 | 270d73a9 |
15 | 182ace5d |
hex | fbd2179 |
264053113 has 2 divisors, whose sum is σ = 264053114. Its totient is φ = 264053112.
The previous prime is 264053093. The next prime is 264053131. The reversal of 264053113 is 311350462.
Together with next prime (264053131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 159441129 + 104611984 = 12627^2 + 10228^2 .
It is a cyclic number.
It is not a de Polignac number, because 264053113 - 217 = 263922041 is a prime.
It is not a weakly prime, because it can be changed into another prime (264053213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132026556 + 132026557.
It is an arithmetic number, because the mean of its divisors is an integer number (132026557).
Almost surely, 2264053113 is an apocalyptic number.
It is an amenable number.
264053113 is a deficient number, since it is larger than the sum of its proper divisors (1).
264053113 is an equidigital number, since it uses as much as digits as its factorization.
264053113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
The square root of 264053113 is about 16249.7111666639. The cubic root of 264053113 is about 641.5498837637.
The spelling of 264053113 in words is "two hundred sixty-four million, fifty-three thousand, one hundred thirteen".
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