Base | Representation |
---|---|
bin | 1100000001000001100111… |
… | …01110001010011100100001 |
3 | 10110120001200121021121102222 |
4 | 12000200303232022130201 |
5 | 11430410320133410132 |
6 | 132110442532120425 |
7 | 5365015060535423 |
oct | 600406356123441 |
9 | 113501617247388 |
10 | 26423506544417 |
11 | 84681676485a4 |
12 | 2b69076a66115 |
13 | 1198958c77b38 |
14 | 674c940b8813 |
15 | 30c509234412 |
hex | 180833b8a721 |
26423506544417 has 2 divisors, whose sum is σ = 26423506544418. Its totient is φ = 26423506544416.
The previous prime is 26423506544389. The next prime is 26423506544447. The reversal of 26423506544417 is 71444560532462.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26401931634961 + 21574909456 = 5138281^2 + 146884^2 .
It is a cyclic number.
It is not a de Polignac number, because 26423506544417 - 214 = 26423506528033 is a prime.
It is not a weakly prime, because it can be changed into another prime (26423506544447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13211753272208 + 13211753272209.
It is an arithmetic number, because the mean of its divisors is an integer number (13211753272209).
Almost surely, 226423506544417 is an apocalyptic number.
It is an amenable number.
26423506544417 is a deficient number, since it is larger than the sum of its proper divisors (1).
26423506544417 is an equidigital number, since it uses as much as digits as its factorization.
26423506544417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19353600, while the sum is 53.
The spelling of 26423506544417 in words is "twenty-six trillion, four hundred twenty-three billion, five hundred six million, five hundred forty-four thousand, four hundred seventeen".
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