Base | Representation |
---|---|
bin | 100110011101110111111… |
… | …000001101111110001001 |
3 | 100100201010012202222001201 |
4 | 212131313320031332021 |
5 | 321302204011104113 |
6 | 5342211341144201 |
7 | 361660213141063 |
oct | 46356770157611 |
9 | 10321105688051 |
10 | 2643416113033 |
11 | 92a080533733 |
12 | 36838a85b061 |
13 | 162371c1c097 |
14 | 91d28ca4733 |
15 | 48b646bdcdd |
hex | 26777e0df89 |
2643416113033 has 2 divisors, whose sum is σ = 2643416113034. Its totient is φ = 2643416113032.
The previous prime is 2643416112991. The next prime is 2643416113097. The reversal of 2643416113033 is 3303116143462.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2361425376249 + 281990736784 = 1536693^2 + 531028^2 .
It is a cyclic number.
It is not a de Polignac number, because 2643416113033 - 217 = 2643415981961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2643416112983 and 2643416113001.
It is not a weakly prime, because it can be changed into another prime (2643426113033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1321708056516 + 1321708056517.
It is an arithmetic number, because the mean of its divisors is an integer number (1321708056517).
Almost surely, 22643416113033 is an apocalyptic number.
It is an amenable number.
2643416113033 is a deficient number, since it is larger than the sum of its proper divisors (1).
2643416113033 is an equidigital number, since it uses as much as digits as its factorization.
2643416113033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 37.
The spelling of 2643416113033 in words is "two trillion, six hundred forty-three billion, four hundred sixteen million, one hundred thirteen thousand, thirty-three".
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