Base | Representation |
---|---|
bin | 100110011101110111111… |
… | …000001101111111001001 |
3 | 100100201010012202222011002 |
4 | 212131313320031333021 |
5 | 321302204011104342 |
6 | 5342211341144345 |
7 | 361660213141214 |
oct | 46356770157711 |
9 | 10321105688132 |
10 | 2643416113097 |
11 | 92a080533791 |
12 | 36838a85b0b5 |
13 | 162371c1c116 |
14 | 91d28ca477b |
15 | 48b646bdd32 |
hex | 26777e0dfc9 |
2643416113097 has 2 divisors, whose sum is σ = 2643416113098. Its totient is φ = 2643416113096.
The previous prime is 2643416113033. The next prime is 2643416113099. The reversal of 2643416113097 is 7903116143462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1948492141456 + 694923971641 = 1395884^2 + 833621^2 .
It is a cyclic number.
It is not a de Polignac number, because 2643416113097 - 26 = 2643416113033 is a prime.
Together with 2643416113099, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2643416113099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1321708056548 + 1321708056549.
It is an arithmetic number, because the mean of its divisors is an integer number (1321708056549).
Almost surely, 22643416113097 is an apocalyptic number.
It is an amenable number.
2643416113097 is a deficient number, since it is larger than the sum of its proper divisors (1).
2643416113097 is an equidigital number, since it uses as much as digits as its factorization.
2643416113097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 47.
The spelling of 2643416113097 in words is "two trillion, six hundred forty-three billion, four hundred sixteen million, one hundred thirteen thousand, ninety-seven".
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