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2644053356513 is a prime number
BaseRepresentation
bin100110011110011101110…
…111000110111111100001
3100100202202121212021210002
4212132131313012333201
5321310010124402023
65342354503345345
7362012051464562
oct46363567067741
910322677767702
102644053356513
1192a37820a138
12368528152255
13162443c5792a
1491d89784169
1548ba05e6b28
hex2679ddc6fe1

2644053356513 has 2 divisors, whose sum is σ = 2644053356514. Its totient is φ = 2644053356512.

The previous prime is 2644053356429. The next prime is 2644053356521. The reversal of 2644053356513 is 3156533504462.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2335603079824 + 308450276689 = 1528268^2 + 555383^2 .

It is a cyclic number.

It is not a de Polignac number, because 2644053356513 - 212 = 2644053352417 is a prime.

It is a super-2 number, since 2×26440533565132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2644053356543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1322026678256 + 1322026678257.

It is an arithmetic number, because the mean of its divisors is an integer number (1322026678257).

Almost surely, 22644053356513 is an apocalyptic number.

It is an amenable number.

2644053356513 is a deficient number, since it is larger than the sum of its proper divisors (1).

2644053356513 is an equidigital number, since it uses as much as digits as its factorization.

2644053356513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888000, while the sum is 47.

The spelling of 2644053356513 in words is "two trillion, six hundred forty-four billion, fifty-three million, three hundred fifty-six thousand, five hundred thirteen".