Base | Representation |
---|---|
bin | 11000101001101111… |
… | …011111011101110001 |
3 | 2112022202012101100012 |
4 | 120221233133131301 |
5 | 413202322304111 |
6 | 20054334304305 |
7 | 1624645205264 |
oct | 305157373561 |
9 | 75282171305 |
10 | 26470119281 |
11 | 10253768441 |
12 | 5168958095 |
13 | 265ac95b98 |
14 | 13d170ccdb |
15 | a4dcb848b |
hex | 629bdf771 |
26470119281 has 2 divisors, whose sum is σ = 26470119282. Its totient is φ = 26470119280.
The previous prime is 26470119233. The next prime is 26470119283. The reversal of 26470119281 is 18291107462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26430630625 + 39488656 = 162575^2 + 6284^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-26470119281 is a prime.
It is a super-2 number, since 2×264701192812 (a number of 22 digits) contains 22 as substring.
Together with 26470119283, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (26470119283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13235059640 + 13235059641.
It is an arithmetic number, because the mean of its divisors is an integer number (13235059641).
Almost surely, 226470119281 is an apocalyptic number.
It is an amenable number.
26470119281 is a deficient number, since it is larger than the sum of its proper divisors (1).
26470119281 is an equidigital number, since it uses as much as digits as its factorization.
26470119281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 41.
The spelling of 26470119281 in words is "twenty-six billion, four hundred seventy million, one hundred nineteen thousand, two hundred eighty-one".
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