Base | Representation |
---|---|
bin | 1100000010100111111010… |
… | …10011011011011011111111 |
3 | 10110202022110011221210210021 |
4 | 12001103331103123123333 |
5 | 11432310310101010221 |
6 | 132152004424353011 |
7 | 5402001063443236 |
oct | 601237523333377 |
9 | 113668404853707 |
10 | 26478428141311 |
11 | 84894904381a3 |
12 | 2b77844015767 |
13 | 11a0b9c554b73 |
14 | 6777c42dbb1d |
15 | 30db70be5041 |
hex | 1814fd4db6ff |
26478428141311 has 2 divisors, whose sum is σ = 26478428141312. Its totient is φ = 26478428141310.
The previous prime is 26478428141303. The next prime is 26478428141357. The reversal of 26478428141311 is 11314182487462.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 26478428141311 - 23 = 26478428141303 is a prime.
It is a super-2 number, since 2×264784281413112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26478428141411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13239214070655 + 13239214070656.
It is an arithmetic number, because the mean of its divisors is an integer number (13239214070656).
Almost surely, 226478428141311 is an apocalyptic number.
26478428141311 is a deficient number, since it is larger than the sum of its proper divisors (1).
26478428141311 is an equidigital number, since it uses as much as digits as its factorization.
26478428141311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2064384, while the sum is 52.
The spelling of 26478428141311 in words is "twenty-six trillion, four hundred seventy-eight billion, four hundred twenty-eight million, one hundred forty-one thousand, three hundred eleven".
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