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265140300053257 is a prime number
BaseRepresentation
bin111100010010010011001001…
…011001100111101100001001
31021202210011110101102212101121
4330102103021121213230021
5234223024313303201012
62335523434453315241
7106563516543065506
oct7422231131475411
91252704411385347
10265140300053257
1177533408206552
12258a1b72035b21
13b4c38139ac705
144968c0511a4ad
15209bd935a4a07
hexf124c9667b09

265140300053257 has 2 divisors, whose sum is σ = 265140300053258. Its totient is φ = 265140300053256.

The previous prime is 265140300053203. The next prime is 265140300053261. The reversal of 265140300053257 is 752350003041562.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 229487232154896 + 35653067898361 = 15148836^2 + 5971019^2 .

It is a cyclic number.

It is not a de Polignac number, because 265140300053257 - 215 = 265140300020489 is a prime.

It is not a weakly prime, because it can be changed into another prime (265140300053267) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132570150026628 + 132570150026629.

It is an arithmetic number, because the mean of its divisors is an integer number (132570150026629).

Almost surely, 2265140300053257 is an apocalyptic number.

It is an amenable number.

265140300053257 is a deficient number, since it is larger than the sum of its proper divisors (1).

265140300053257 is an equidigital number, since it uses as much as digits as its factorization.

265140300053257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756000, while the sum is 43.

The spelling of 265140300053257 in words is "two hundred sixty-five trillion, one hundred forty billion, three hundred million, fifty-three thousand, two hundred fifty-seven".