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265162345001 is a prime number
BaseRepresentation
bin1111011011110011101…
…0000100101000101001
3221100102121201210021122
43312330322010220221
513321023030020001
6321451445145025
725104653513141
oct3667472045051
9840377653248
10265162345001
11a250025a494
12434823bb175
131c00a439b78
14cb96415921
156d6deeab1b
hex3dbce84a29

265162345001 has 2 divisors, whose sum is σ = 265162345002. Its totient is φ = 265162345000.

The previous prime is 265162344943. The next prime is 265162345003. The reversal of 265162345001 is 100543261562.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 262860264601 + 2302080400 = 512699^2 + 47980^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-265162345001 is a prime.

It is a super-2 number, since 2×2651623450012 (a number of 24 digits) contains 22 as substring.

Together with 265162345003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (265162345003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132581172500 + 132581172501.

It is an arithmetic number, because the mean of its divisors is an integer number (132581172501).

Almost surely, 2265162345001 is an apocalyptic number.

It is an amenable number.

265162345001 is a deficient number, since it is larger than the sum of its proper divisors (1).

265162345001 is an equidigital number, since it uses as much as digits as its factorization.

265162345001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 265162345001 in words is "two hundred sixty-five billion, one hundred sixty-two million, three hundred forty-five thousand, one".